PHP实现数组根据某个字段进行水平合并，横向合并案例分析

本文实例讲述了php实现数组根据某个字段进行水平合并，横向合并。分享给大家供大家参考，具体如下：

php数组水平合并，横向合并，两条数据合并成一行

需求

将两个素组中日期相同的合并成一行

数组a

array(  [0] => array    (      [date] => 2019-04-02      [today_pay_money] => 168.00      [today_pay_num] => 1      [yesterday_pay_money] => 999.00      [yesterday_pay_num] => 1    )  [1] => array    (      [date] => 2019-04-09      [today_pay_mo你认为练书法有什么益处ney] => 0.01      [today_pay_num] => 1      [yesterday_pay_money] => 0.00      [yesterday_pay_num] => 0   东南大学迎新网 )  [2] => array    (      [date] => 2019-05-05      [today_pay_money] =>摘抄100字 0.01      [today_pay_num] => 1      [yesterday_pay_money] =全国节能宣传周> 2.00      [yesterday_pay_num] => 1    )  [3] => array    (      [date] => 2019-05-11      [today_pay_money] => 0.00      [today_pay_num] => 0      [yesterday_pay_money] =>      [yesterday_pay_num] => 1    ))

数组b

array(  [0] => array    (      [date] => 2019-05-07      [today_pay_money1] => 0      [today_pay_num1] => 0      [yesterday_pay_money1] => 0      [yesterday_pay_num1] => 0    )  [1] => array    (      [date] => 2019-05-11      [today_pay_money1] => 0      [today_pay_num1] => 0      [yesterday_pay_money1] => 1      [yesterday_pay_num1] => 1    ))

需要格式

array(  [2019-04-02] => array    (      [date] => 2019-04-02      [today_pay_money] => 168.00      [today_pay_num] => 1      [yesterday_pay_money] => 999.00      [yesterday_pay_num] => 1    )  [2019-04-09] => array    (      [date] => 2019-04-09      [today_pay_money] => 0.01      [today_pay_num] => 1      [yesterday_pay_money] => 0.00      [yesterday_pay_num] => 0    )  [2019-05-05] => array    (      [date] => 2019-05-05      [today_pay_money] => 0.01      [today_pay_num] => 1      [yesterday_pay_money] => 2.00      [yesterday_pay_num] => 1    )  [2019-05-11] => array    (      [date] => 2019-05-11      [today_pay_money] => 0.00      [today_pay_num] => 0      [yesterday_pay_money] =>      [yesterday_pay_num] => 1      [today_pay_money1] => 0      [today_pay_num1] => 0      [yesterday_pay_money1] => 1      [yesterday_pay_num1] => 1    )  [2019-05-07] => array    (      [date] => 2019-05-07      [today_pay_money1] => 0      [today_pay_num1] => 0      [yesterday_pay_money1] => 0 双十二销售额     [yesterday_pay_num1] => 0    ))

代码实现

先将a,b数组合并，判断当前日期下是否空，空的话直接赋值，不空的话，将已有素组和当前数组合并

$total = array_merge($a,$b));$res = array();foreach ($total as $k => $v) {  if (empty($res[$v['date']]))  $res[$v['date']] = $v;  el  $res[$v['date']]= array_merge($res[$v['date']],$v);}