STEP 3 2012

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Sixth Term Examination Papers                  9475 MATHEMATICS 3 Afternoon WEDNESDAY 27 JUNE 2012  Time: 3 hours
Additional Materials: Answer Booklet
Formulae Booklet
INSTRUCTIONS TO CANDIDATES
Plea read this page carefully, but do not open this question paper until you are
told that you may do so.
Write your name, centre number and candidate number in the spaces on the answer
booklet.
Begin each answer on a new page.
Write the numbers of the questions you answer in the order attempted on the front of the answer booklet.
INFORMATION FOR CANDIDATES
Each question is marked out of 20. There is no restriction of choice.
初中英语语法书All questions attempted will be marked.meanshift
Your final mark will be bad on the six questions for which you gain the highest marks.
You are advid to concentrate on no more than six questions. Little credit will be given for fragmentary answers.
You are provided with a Mathematical Formulae Booklet.
Calculators are not permitted.
Plea wait to be told you may begin before turning this page.
_____________________________________________________________________________ Thi
s question paper consists of 8 printed pages and 4 blank pages.
BLANK PAGE
Section A:Pure Mathematics
1Given that z=y n
d y
d x
2
,show that
d z
vientiane
d x
=y n−1
d y
d x
n
d y
d x
2
+2y
d2y
d x2
.
(i)U the above result to show that the solution to the equation
d y d x  2
+2y
circle of friendsd2y
d x2
=
y(y>0)
that satisfies y=1and d y
d x
=0when x=0is y=
3
8
x2+1
2
3.
(ii)Find the solution to the equation
d y d x  2
−y d
2y
d x2
英语学习网站大全+y2=0
that satisfies y=1and d y
d x
=0when x=0.
2In this question,|x|<1and you may ignore issues of convergence.
(i)Simplify
(1−x)(1+x)(1+x2)(1+x4)···(1+x2n), where n is a positive integer,and deduce that
1 1−x =(1+x)(1+x2)(1+x4)···(1+x2n)+
x2n+1
1−x
.
Deduce further that
ln(1−x)=−
草莓的英文单词
r=0
ln
1+x2r
,
and hence that
1 1−x =
1
1+x
+
2x
1+x2
+
4x3英语四级单词下载
1+x4
+···.
(ii)Show that
1+2x 1+x+x2=
1−2x
1−x+x2
+
2x−4x3
1−x2+x4
+
4x3−8x7
1−x4+x8
+···.
2
3It is given that the two curves
y=4−x2and mx=k−y2,
where m>0,touch exactly once.
(i)In each of the following four cas,sketch the two curves on a single diagram,noting
the coordinates of any interctions with the axes:
trf
(a)k<0;
(b)0<k<16,k/m<2;
(c)k>16,k/m>2;
(d)k>16,k/m<2.
(ii)Now t m=12.
Show that the x-coordinate of any point at which the two curves meet satisfies
x4−8x2+12x+16−k=0.
Let a be the value of x at the point where the curves touch.Show that a satisfies
a3−4a+3=0
杂志社英文and hencefind the three possible values of a.
Derive also the equation
k=−4a2+9a+16.
Which of the four sketches in part(i)ari?
4(i)Show that
∞ n=1n+1
n!
=2e−1
arms
and
∞ n=1(n+1)2
n!
=5e−1.
Sum the ries
n=1
(2n−1)3
n!
.
(ii)Sum the ries
n=0
(n2+1)2−n
(n+1)(n+2)
,giving your answer in terms of natural logarithms.
3
5(i)The point with coordinates(a,b),where a and b are rational numbers,is called:
an integer rational point if both a and b are integers;
a non-integer rational point if neither a nor
b is an integer.
(a)Write down an integer rational point and a non-integer rational point on the circle
x2+y2=1.
(b)Write down an integer rational point on the circle x2+y2=2.Simplify
(cosθ+√
m sinθ)2+(sinθ−
m cosθ)2
and hence obtain a non-integer rational point on the circle x2+y2=2.
(ii)The point with coordinates(p+√
2q,r+
2s),where p,q,r and s are rational numbers,
is called:
an integer2-rational point if all of p,q,r and s are integers;
a non-integer2-rational point if none of p,q,r and s is an integer.
(a)Write down an integer2-rational point,and obtain a non-integer2-rational point,
on the circle x2+y2=3.
(b)Obtain a non-integer2-rational point on the circle x2+y2=11.
(c)Obtain a non-integer2-rational point on the hyperbola x2−y2=7.
6Let x+i y be a root of the quadratic equation z2+pz+1=0,where p is a real number.Show that x2−y2+px+1=0and(2x+p)y=0.Show further that
either p=−2x or p=−(x2+1)/x with x=0.
Hence show that the t of points in the Argand diagram that can(as p varies)reprent roots of the quadratic equation consists of the real axis with one point missing and a circle.This t of points is called the root locus of the quadratic equation.
Obtain and sketch in the Argand diagram the root locus of the equation
pz2+z+1=0
and the root locus of the equation
pz2+p2z+2=0.
4

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