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google的一个API接口：引用搜索结果

更新时间:2023-06-09 03:58:32 阅读：评论：0

ajax arch功能参考：so.csdn/arch?t=thread&q=ajax%20arch

/intl/zh-CN/apis/loader/

好听的男英文名字/intl/zh-CN/apis/webarch/docs/

AJAX Search API

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一简单的Google API搜索例子

首先看一个Java代码的例子

需要两个jar的支持

commons-httpclient.jar

commons-codec-1.3.jar

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import java.io.UnsupportedEncodingException;

import java.URLEncoder;

import s.httpclient.DefaultHttpMethodRetryHandler;

import s.httpclient.HttpClient;

import s.httpclient.HttpStatus;

import hods.GetMethod;

import s.httpclient.params.HttpMethodParams;

import org.json.JSONArray;

import org.json.JSONObject;

public class GoogleQuery {

public GoogleQuery() throws UnsupportedEncodingException {

String query =&de("AOP示例+site:blog.csdn/zhjb1025", "UTF-8");//站内搜索

//String query =&de("AOP示例", "UTF-8");

for (int i = 0; i < 3; i++) { 仁爱英语七年级上册教案

makeQuery("/ajax/rvices/arch/web?start="

+ i * 8 + "&rsz=large&v=1.0&q=" + query);

}

private void makeQuery(String query) {

try {

HttpClient httpClient = new HttpClient();

GetMethod getMethod = new GetMethod(query);

uteMethod(getMethod);

Params().tParameter(HttpMethodParams.RETRY_HANDLER,

new DefaultHttpMethodRetryHandler());

int statusCode =&uteMethod(getMethod);

if (statusCode != HttpStatus.SC_OK) {

println("Method failed: "

+&StatusLine());

apu是什么 }

byte[] responBody =&ResponBody();

String respon = new String(responBody, "UTF-8");

JSONObject json = new JSONObject(respon);

System.out.println("Total results = "

+&JSONObject("responData")

.getJSONObject("cursor").getString(

"estimatedResultCount"));

JSONArray ja =&JSONObject("responData").getJSONArray(

"results");

System.out.println(" Results:");

for (int i = 0; i < ja.length(); i++) {

初一英语单词表

JSONObject j =&JSONObject(i);

System.out.String("titleNoFormatting"));

System.out.String("url"));

中英网

System.out.("content"));

}

} catch (Exception e) {

println("Something went&");

e.printStackTrace();

}

System.out.println("--------------------------------------------");

}

public static void main(String args[]) {

try {

new GoogleQuery();

} catch (UnsupportedEncodingException e) {

e.printStackTrace();

}

再来一个js的例子

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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "www.w3/TR/xhtml1/DTD/xhtml1-strict.dtd">

<head>

<title>My Google AJAX Search API Application</title>

<mce:script src="/jsapi?key=你申请的key" mce_src="/jsapi?key=你申请的key" type="text/javascript"></mce:script>

<mce:script language="Javascript" type="text/javascript"><!--

google.load("arch", "1");

function OnLoad() {

// Create a arch control

var archControl = new google.arch.SearchControl();

buy// Add in a full t of archers

var localSearch = new google.arch.LocalSearch();

archControl.addSearcher(localSearch);

archControl.addSearcher(new google.arch.WebSearch());

archControl.addSearcher(new google.arch.VideoSearch());

archControl.addSearcher(new google.arch.BlogSearch());

// Set the Local Search center point

//localSearch.tCenterPoint("New York, NY");

walking on sunshine// Tell the archer to draw itlf and tell it where to attach

archControl.ElementById("archcontrol"));

// Execute an inital arch

ute("java");

}

google.tOnLoadCallback(OnLoad);

decorate// --></mce:script>

</head>

<body>

</body>

</html>

补充：

有问题的小程序，可以参考：“google搜出来的结果远不是4个，但为什么我用firebug调试的时候发现sults.length的值为4呢？”

function archComplete(archControl, archer) {

for (var i=0; i < sults.length; i++) {

// Do whatever you want with the results

}

function OnLoad() {

var archControl = new google.arch.SearchControl();

var webSearch = new google.arch.WebSearch();

archControl.addSearcher(webSearch);

archControl.ElementById("archcontrol"));

archControl.tSearchCompleteCallback(this, archComplete);

ute('Google')

}

google.tOnLoadCallback(OnLoad);

jquery google API AjaxAPI 库

调用Google API的代码库，可以有效的减少自己站上的流量。比如Jquery，gzip后有19K，调用Google Api，不仅省去了流量，如果大家的网站都这么做的话，由于缓存原因，很多网站用到的话，就不需要重复加载了，非常节省资源，和加载时间。

waffle采用Ajax动态加载google的API中jquery库的代码是这样的：

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