MATH LEVEL2
抱歉这个看得比较少……
如何使用CASIO 学生用计算器……（本人认为完全不用TI等高级货…中国小孩儿～手绘快～）
MODE 2SD统计，
输入方法：A;B M+ 一组……………………之后SHIFT 【S-VAR】
standard deviation 标准偏差Xon-1
其他不用说了
MODE3REG求回归函数吧……
常用的是LIN线性，LOG对数，QUAD二次,（废话……）
输入方法A,B M+ 一组…………………………之后SHIFT 【S-VAR】
线性：Y= a+ bX
二次：Y=a+bX+cX2
对数：Y=a+bInX
indirect proof反证In an indirect proof of ―if p, then q,‖ you assume the negative of the conclusion rhombus 菱形
parallelogram 平行四边形
slant height斜高负离子机
pentagon五边形
挑几个我当时觉得有问题的给大家找找自信……
41.
If and , then AB =
(A)
(B)
(C)
工作表现评价(D)
(E)
You left this question blank. You should have lected B. Explanation
The number of rows in A equals the number of columns in form product matrix AB , multiply each row of B by each c arranging the six resulting entries in a 3-row, 2-column ma (B row 1)(A col. 1) = (3)(4) + (0)(1) = 12 (B row 1)(A
= –9
(B row 2)(A col. 1) = (1)(4) + (5)(1) = 9 (B row 2)(A = 7
(B row 3)(A col. 1) = (–2)(4) + (4)(1) = –4
(B row 3)(A (4)(2) = 14
Topic:
46. What is the least positive
integer n for
which 2n has 16
digits?
(A) 48
(B) 49
(C) 50
(D) 51
(E) 55
中药天麻You left this question blank. You should have lected B. Explanation
Since this problem asks you to solve for n when n is an exponent, you need to u logarithms in your solution. Your first step, though, should be to t up an inequality. The smallest positive integer with 16 digits is 1015, since it
is a 1 followed by 15 zeros. Since 2n must be equal to or greater than the
smallest positive 16-digit integer, you can t up the following inequality:
Now take the logarithm of each side:
Apply the power rule of logarithms to the inequality to get:
Thus the least positive integer n
is 50.
15.
The height of the pyramid in the figure below is three times the height of the box. The area of the ba of the pyramid is half the area of the ba of the box. If the volume of the pyramid is V , what is the volume of the box in terms of V ?
(A
)展报
V (B ) V (C )
2V (D ) V (E )
4V
B is not the correct answer. You should have lected C. Explanation
Let the height of the pyramid be x and the ba area of the pyramid be y . So: volume of the pyramid = 1/3 xy.Then, let the height of the box be p and the ba area of the box be q . The volume of the box is thus pq . From the information given, x = 3p and y = 1/2 q , so it’s possible to solve for the volume of the box in terms of x and y :
volume of box = pq
= 2y
= xy
Since V = 1 /3 xy , the volume of the box in terms of V is 2V .
36.
A two-sided coin is flipped four times. Given that the coin landed heads up more than twice, what is the probability that it landed heads up all four times?
(A
始丰溪) (B
) (C
一个诚实的人)
(D ) (E )
A is not the correct answer. You should have lected C. Explanation
It is given that the coin landed heads up more than twice —in other words, it landed heads up either three times or four times. To find the probability that it landed heads up four times given that it landed heads up more than twice, it is necessary to divide the probability that it landed heads up four times by the probability that it landed heads up more than twice, i.e., P (4)/P (>2)= P (4)/P (3)+P (4). The probability that the coin landed heads up four times out of four toss is easy: (1 /2)4 = 1/16. Now the probability that the coin landed heads up three times is a little more complicated: the first toss could have been tails and the rest heads, or the cond toss could have been tails and the rest heads, and so on. In all, any of the four toss could have been the tails toss, with equal probability,
1 /16. So, the probability that the coin lands heads up exactly three times is 4 1/ 16 = 4 /16. Thus, the answer is 1/16 (4/ 16 + 1 /16) = 1/16
5
/ 16 = 1 /5.
Topic:
英语作文翻译器
Probability
40. In an arithmetic quence, a 5 = a 10 – 3 and a 3 = –2. Between which two小学生春节对联
concutive terms does 0 lie?
(A )
a 4 and a 5 (B )
a 5 and a 6 (C )
a 6 and a 7 (D )
a 7 and a 8 (E )
a 9 and a 10
B is not the correct answer. You should have lected C. Explanation
Becau this is an arithmetic quence, the difference between concutive terms is constant. The first step in answering the question is finding this common difference. By knowing a 5 = a 10 – 3, t up and solve the equation a n +1 – a n = 3/10–5 = 0.6. Now list the terms of the quence, starting with a 3. a 3 = –2, a 4 = –1.4, a 5 = –0.8, a 6 = –0.2, a 7
= 0.4, and so on. The question is answered: 0 lies between the sixth and venth terms of the quence.
Topic:
Sequences
49.
What is ?
(A) 0 (B) 1 (C) –2 (D) 4
(E) The limit does not
exist.
