习题10答案
一、选择题、填空题
答案：
1. C B
2. D
3. D
4. D
sigg5. B
synergy6. C
7. B
8. A
9. B 10. C
11. A 12. B 13. A 14. C
二、找错、运行结果
1．
错误原因：具有两个缺省构造函数（重复定义缺省构造函数）
2．
运行结果：
Default constructor called.
Constructor called.
0,0
6,8
6,8
Destructor called.
0,0
Destructor called.
3．
答案（版本1）：（使用左框中的程序产生的结果）
0,0,Constructor called.
6,8,Constructor called.
6,8,Copy constructor called.
0,0,Constructor called.
6,8,Copy constructor called.
6,8,
3,7,Copy constructor called.
3,7,Destructor called.
3,7,Destructor called.
3,7,6,8,
3,7,Destructor called.
6,8,Destructor called.
6,8,Destructor called.
0,0,Destructor called.
答案（版本2）：（使用右框中的程序产生的结果）
0,0,Constructor called.
6,8,Constructor called.
6,8,Copy constructor called. 0,0,Constructor called.
6,8,
3,7,3,7,
3,7,Destructor called.
memorial day3,7,Destructor called.
6,8,Destructor called.
0,0,Destructor called.
4．
运行结果：
0,0,Constructor called.
6,8,Constructor called.
6,8,
3,7,
3,7,Destructor called.
3,7,Destructor called.
6,8,Destructor called.
0,0,Destructor called.
5．
运行结果：
内训课
(3,0)Construct
(4,0)Construct
(0,0)Construct
(5,6)Construct
(0,0)Construct
(3,0)
(4,0)
(0,0)
(5,6)
(0,0)
Exit main( )
(0,0)Destruct
(5,6)Destruct
(0,0)Destruct
(4,0)Destruct
(3,0)Destruct
6．运行结果：
8,0x0012FF7C
9,0x0012FF78
7．
运行结果：
1,2,3
4,5,6,7,8
Different! copied!
1,2,3
1,2,3
Different! copied!
Different! copied!
1,2,3
1,2,3
三、编程题
1．
答案：
#include<iostream.h>
class complex
{
double real,image;
public:
void treal( double r)
{ real=r; }
pelivoid timage(double i)
{ image=i; }
double getreal( )
{ return(real); }
double getimage( )
{ return(image); }
void output()
{ if(image<0)
cout<<real<<image<<'i';
el if(image>0)
cout<<real<<'+'<<image<<'i';
el
cout<<real;
cout<<'\n';
}
};
void main()
{ complex c1,c2;
c1.timage(2);
cout<<"c1=";
c1.output();
c2.timage(4);
cout<<"c2=";
c2.output();
double a,b;
al();
image();
cout<<a<<','<<b<<endl;
}
2．
答案：
#include<iostream.h>
#include<math.h>
class Line
{
private:
int x1,y1,z1,x2,y2,z2;
negro的复数
public:
海啸奇迹 豆瓣
void SetPoint1(int x,int y,int z)
{ x1=x;y1=y;z1=z; }
void SetPoint2(int x,int y, int z)
{ x2=x;y2=y;z2=z; }
double Length()
{ return (sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)+(z1-z2)*(z1-z2))); } void GetPoint1(int *px,int *py,int *pz)
{ *px=x1; *py=y1; *pz=z1; }
void GetPoint2(int &x,int &y, int &z)
{ x=x2; y=y2; z=z2; }
void Output()
{
cout<<"端点的坐标为："<<"("<<x1<<","<<y1<<","<<z1<<")"<<","
<<"("<<x2<<","<<y2<<","<<z2<<")"<<endl;
cout<<"线段长度为："<<Length()<<endl;
}
};
void main()
{ Line line;
int x,y,z;
cout<<"请输入第1点坐标：";
cin >> x >> y >> z ;
line.SetPoint1(x,y,z);
cout<<"请输入第2点坐标：";
cin >> x >> y >> z ;
line.SetPoint2(x,y,z);
line.Output();
int a,b,c;
line.GetPoint1(&a,&b,&c);
bvcout<<a<<','<<b<<','<<c<<endl;
line.GetPoint2(a,b,c);
cout<<a<<','<<b<<','<<c<<endl; }
3．
答案：
#include<iostream.h>
#include<math.h>
class Point
{
int x,y;
public:
void SetPoint(int x1, int y1)
{ x=x1; y=y1; }
void GetPoint(int &x1, int &y1)
{ x1=x; y1=y; }
void Setx(int xx)
{ x=xx; }
void Sety(int yy)
{ y=yy; }
int Getx()
{ return x; }
int Gety()
{ return y; }
};
class Triangle
{
Point p[3];
public:
void SetPoint1(int xx, int yy)
{ p[0].SetPoint(xx,yy); }
void SetPoint2(int xx, int yy)
{ p[1].SetPoint(xx,yy); }
void SetPoint3(int xx, int yy)英语人才
{ p[2].SetPoint(xx,yy); }
double Distance(int i, int j)
{
int x1,x2,y1,y2;
unesco是什么意思
p[i-1].GetPoint(x1,y1);
