利用switch语句解决问题：定期存款利息计算器

利⽤switch语句解决问题：定期存款利息计算器

1#include

2int main ( )

3{

4 int type;

5 double money, period, rate, interest;

6 printf("欢迎使⽤利息计算器！n");

7 printf("请输⼊存款⾦额：");

8 scanf("%lf", &money);

9 printf("======存款期限======n");

10 printf("1. 3个⽉ n");

11 printf("2. 6个⽉n");

12 printf("3. ⼀年 n");

13 printf("4. ⼆年n");

14 printf("5. 三年n");

15 printf("6. 五年n");

16 printf("请输⼊存款期限的代号：");

17 scanf("%d", &type);

18 if (type>=1 && type <=6)

19 {

20 switch(type) //在if中嵌⼊了switch分情况处理

21 {

22 case 1:

23 period = 0.25;

24 rate = 0.031;

25 break;

26 case 2:

27 period = 0.5;

28 rate = 0.033;

29 break;

30 case 3:

31 period = 1;

32 rate = 0.035;

33 break;

34 case 4:

35 period = 2;

36 rate = 0.044;

37 break;

38 case 5:

39 period = 3;

40 rate = 0.05;

41 break;

42 case 6:

43 period = 5;

44 rate = 0.055;

45 break;

46 }

47 interest = money * period * rate;

48 printf("到期利息为：%.2lf 元，本息合计共 %.2lf 元。n", interest, interest + money);

49 }

50 else

51 printf("选择存款类型错误！n");

52 printf("感谢您的使⽤，欢迎下次光临！n");

53 return 0;

54}