马鞍面

马鞍线matlab,使⽤matlab编程，怎样画出⼼形线和马鞍⾯？

2018-11-21回答

你的问题确实很⿇烦．

%问题1.

clear

ax1=subplot(1,2,1);

t=0:.01*pi:2*pi;

f1=polar(t,1+cos(t));

title('⼼形线');

legend(f1,'r=1+cost')

ax2=subplot(1,2,2);

x1=linspace(-40,20,40);

y1=linspace(-40,20,40);

[xx1,yy1]=meshgrid(x1,y1);

zz1=xx1.*yy1;

f2=surf(xx1,yy1,zz1);

title('马鞍⾯');

legend(f2,'z=x^2-y^2','location','northwest')

xlabel('x轴')

ylabel('y轴')

zlabel('z轴')

axis([-4020-4])

tallowaxesrotate(rotate3d,ax1,fal);

gridon

%问题2(给你四个程序，你⾃⼰挑吧)：

%1)

clear

[x,y,z]=sphere(200);

i=find(x.^2+y.^2-x>=0&x.^2+y.^2+z.^2<1);

z(i)=nan;

mesh(x,y,z)

holdon

t=0:pi/20:2*pi;

x=(cos(t)+1)/2;

y=sin(t)/2;

z=linspace(-1.2,1.2,length(t));

x=meshgrid(x);

y=meshgrid(y);

z=[meshgrid(z)]';

surf(x,y,z)

xlabel('x'),ylabel('y'),zlabel('z')

title('球⾯x^2+y^2+z^2=1和圆柱⾯x^2+y^2=x所围成的区域')

rotate3don

%2)

clear

[x,y,z]=sphere(20);

mesh(x,y,z)

hiddenon

holdon

axiqual

t=0:pi/20:2*pi;

x=(cos(t)+1)/2;

y=sin(t)/2;

z=linspace(-1.2,1.2,length(t));

x=meshgrid(x);

y=meshgrid(y);

z=[meshgrid(z)]';

surf(x,y,z)

xlabel('x'),ylabel('y'),zlabel('z')

rotate3don

%3)

[x,y,z]=sphere(200);

i=find(x.^2+y.^2-x<=0&x.^2+y.^2+z.^2>=1);

z(i)=nan;

mesh(x,y,z)

hiddenon

holdon

ezplot('x^2+y^2=x')

title('球⾯x^2+y^2+z^2=1和圆柱⾯x^2+y^2=x所围成的区域')

rotate3don

%4)

[x,y,z]=sphere(200);

i=find(x.^2+y.^2-x>=0);

z(i)=nan;

mesh(x,y,z)

hiddenon

holdon

ezplot('x^2+y^2=x')

title('球⾯x^2+y^2+z^2=1和圆柱⾯x^2+y^2=x所围成的区域')

rotate3don